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10-09-2016
Chemistry

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what is the mass, in grams of a pure iron cube that has a volume of 4.20cm^3

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10-09-2016

[tex]d_{Fe}=7874\frac{kg}{m^{3}}=7,874\frac{g}{cm^{3}}\\ V=4,2cm^{3}\\\\ m=dV=7,784\frac{g}{cm^{3}}*4,2cm^{3}\approx 32,7g[/tex]

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