adriennep03
adriennep03 adriennep03
  • 10-03-2021
  • Mathematics
contestada

The law of cosines is a^2+b^2-2abcos(C). Find the value of 2abcos(C).
A. 37
B. -40
C. 40
D. 20​

The law of cosines is a2b22abcosC Find the value of 2abcosCA 37B 40C 40D 20 class=

Respuesta :

MrRoyal
MrRoyal MrRoyal
  • 15-03-2021

Answer:

A. 37

Step-by-step explanation:

Given

The attached triangle and

[tex]c^2 = a^2 + b^2 -2abcos(C)[/tex]

Required

Find [tex]2abcos(C)[/tex]

From the attachment:

[tex]a = 4[/tex]

[tex]b = 5[/tex]

[tex]c = 2[/tex]

So, we have:

[tex]c^2 = a^2 + b^2 -2abcos(C)[/tex]

[tex]2^2=4^2 + 5^2 -2abcos(C)[/tex]

[tex]4=16 + 25 -2abcos(C)[/tex]

Collect like terms

[tex]2abcos(C)=16 + 25 -4[/tex]

[tex]2abcos(C)=37[/tex]

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