From the top of a tower, a stone is thrown up and it reaches the ground in time t₁. A second stone is thrown down with the same speed and it reaches the ground in time t₂. A third stone is released from rest and it reaches the ground in time t₃.
a. t₃ = 1/2 (t₁ + t₂)
b. t₃ = √t₁t₂
c. (1/t₃) = (1/t₂) - (1/t₁)
d. t₃² = (t₁²)-(t₂²)