rojasadan366
rojasadan366 rojasadan366
  • 12-11-2018
  • Mathematics
contestada

solve for the linear system by using substitution
x=6-4y
2x-3y=1

Respuesta :

trishavidyanand
trishavidyanand trishavidyanand
  • 12-11-2018

Hey!

So heres how you would go about doing this:

x = 6-4y

2x - 3y = 1

Plug the value of x which is 6 - 4y into the second equation:

2(6 - 4y) - 3y = 1

12 - 8y - 3y = 1

12 - 11y = 1

-11y = -11

y = 1

Now plug this back into the first equation which gives you x's value:

x = 6 - 4y

x = 6 - 4(1)

x = 6 - 4

x = 2

The answer is:

x = 2

y = 1

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