Hello from MrBillDoesMath!
Answer:
The solution set is the set all all real number m
Discussion:
3(2m-1) <= 6m-2 =>
3*2m - 3*1 <= 6m-2 =>
6m - 3 <.= 6m-2 => (Subtract 6m from both sides)
0-3 <= -2 =>
-3 < = -2
As -3 <=-2 is always true the solution set is the set all all real number m
Regards,
MrB
