gustyduck gustyduck

10-06-2019
Mathematics

contestada

what are the roots of the equation
[tex] {x}^{2} - 16x + 89 = 0[/tex]
in simplest a+bi form?

Respuesta :

LammettHash LammettHash

10-06-2019

By completing the square,

[tex]x^2-16x+89=x^2-16x+64+25=(x-8)^2+25=0[/tex]

[tex](x-8)^2=-25[/tex]

[tex]x-8=\pm\sqrt{-25}[/tex]

[tex]x=8\pm5i[/tex]

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