Answer:
[tex]f^{-1}(x)=\sqrt[3]{x-3}+9[/tex]
Step-by-step explanation:
Let y = f(x)
y = (x - 9)³ + 3 - Now we need to solve for x
y - 3 = (x - 9)³
∛(y - 3) = x - 9
∛(y - 3) + 9 = x
Now we replace x with [tex]f^{-1}[/tex] and y with x:
[tex]f^{-1}(x)=\sqrt[3]{x-3}+9[/tex]
