tatielder6754 tatielder6754
  • 11-02-2020
  • Chemistry
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Determine the molality of an aqueous solution prepared by dissolving 0.112 moles of licl in 13.7 moles of h2o.

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anfabba15
anfabba15 anfabba15
  • 11-02-2020

Answer:

Molality is 0.45 mol/kg for the LiCl

Explanation:

Molality → Moles of solute in 1kg of solvent

Let's convert the moles of solvent, water to mass (g)

Afterwards we need to convert the mass from g to kg

Molality → mol / kg

First step: 13.7 mol . 18 g / 1mol = 246.6 g

2nd step: 246.6 g . 1kg / 1000 g = 0.2466 kg

Molality → mol/kg → 0.112 moles / 0.2466 kg → 0.45 molal

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