lionalmessi1977 lionalmessi1977
  • 10-08-2020
  • Mathematics
contestada

radical 16 * redical 12

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Аноним Аноним
  • 10-08-2020

[tex]\sqrt{16}\times\sqrt{12}[/tex]

$=\sqrt{4^2}\times\sqrt{2^2\cdot3}$

$=4\times2\sqrt3=8\sqrt3$

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