Answer:
it's not possible
Step-by-step explanation:
let's say that we have
[tex]x,x+1,x+2,x+3[/tex]
so twice the last integer is
[tex]2(x)\\\\=2x[/tex]
and the second integer is
[tex]x+1[/tex]
so the sum of both is 212
[tex]2x+x+1=212\\\\3x+1=212\\\\3x+1-1=212-1\\\\3x=211\\\\x=70.3333...[/tex]
so as we can see there aren't those integers
