alexamedrano15 alexamedrano15
  • 11-10-2020
  • Mathematics
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Find f'(x) for f(x) = cos^2(3x^3).

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cromulent
cromulent cromulent
  • 11-10-2020

[tex]f(x) = \cos^2(3x^3)\\f'(x) = \frac{d}{dx}[\cos^2(3x^3)]\\= 2\cos(3x^3) \cdot \frac{d}{dx}[cos(3x^3)]\\= 2\cos(3x^3) \cdot (-\sin(3x^3)) \cdot \frac{d}{dx}[3x^3]\\= 2\cos(3x^3) \cdot (-\sin(3x^3)) \cdot 9x^2\\= -18x^2\cos(3x^3)\sin(3x^3)[/tex]

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