Answer:
[tex]x>7[/tex]
Step-by-step explanation:
[tex]We\ are\ given:\\-3<x-10\\Now,\ we\ can\ deal\ with\ inequalities\ in\ the\ way\ we\ do\ for\ equalities.\\Hence,\\-3<x-10\\-3+(10)<x-10+(10)\ [Adding\ the\ term\ (10)\ to\ both\ LHS\ and\ RHS]\\Hence,\\-3+10<x-10+10\\7<x+0\\7<x\\Or,\\x>7[/tex]
