Respuesta :

Nirina7
first, the main formula is d [sin^-1(u(x))] / dx  = u' (x) / sqrt(1 - u^2(x))
let be u(x) = 5x,  u'(x) = 5, and u^2(x) = 25x^2
so if If y=sin^-1(5x), then dy/dx=  5/ sqrt (1 - 25x^2)