Respuesta :

samanthadidonna13

Answer:

No, it is not a function.

Step-by-step explanation:

mhanifa

Answer:

  • No

Step-by-step explanation:

Given equation:

  • y^2-x^2=16

Convert this to:

  • y = ± [tex]\sqrt{x^2 + 16}[/tex]

As we see each x-coordinate has two y-values referenced, it doesn't pass the vertical line test, this is not a function.