Respuesta :
Answer:
D. 0.676 moles
General Formulas and Concepts:
Math
Pre-Algebra
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
- Left to Right
Chemistry
Atomic Structure
- Reading a Periodic Tables
- Compounds
- Moles
Stoichiometry
- Using Dimensional Analysis
Explanation:
Step 1: Define
[Given] 56.1 g Na₃N
[Solve] moles Na₃N
Step 2: Identify Conversions
[PT] Molar Mass of Na - 22.99 g/mol
[PT] Molar Mass of N - 14.01 g/mol
Molar Mass of Na₃N - 3(22.99) + 14.01 = 82.98 g/mol
Step 3: Convert
- [DA] Set up: [tex]\displaystyle 56.1 \ g \ Na_3N(\frac{1 \ mol \ Na_3N}{82.98 \ g \ Na_3N})[/tex]
- [DA] Multiply/Divide [Cancel out units]: [tex]\displaystyle 0.676067 \ mol \ Na_3N[/tex]
Step 4: Check
Follow sig fig rules and round. We are given 3 sig figs.
0.676067 mol Na₃N ≈ 0.676 mol Na₃N