Respuesta :

linh1903

Answer:

I think it's

2 HgO (s) → 2 Hg (l) + O2 (g)

Step-by-step explanation:

This is an oxidation-reduction (redox) reaction:

2 HgII + 4 e- → 2 Hg0

(reduction)

2 O-II - 4 e- → 2 O0

(oxidation)