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  • 10-08-2021
  • Mathematics
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Аноним Аноним
  • 10-08-2021

[tex]\huge\mathsf\green{ANSWER}:—[/tex]

[tex]option \: c \: \sqrt{4} \: is \: the \: correct \: option[/tex]

Explanation :-

[tex] \sqrt{4} = \sqrt{2 \times 2} = 2[/tex]

But irrational numbers are the numbers that are not rational numbers but 2 is a rational number that's why option c is correct .

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