Respuesta :

We have:

[tex]\cos (\frac{\pi}{6})=\frac{\sqrt[]{3}}{2}[/tex]

And

[tex]\cos (\frac{\pi}{3})=\frac{1}{2}[/tex]

After that, we proceed as follows:

[tex]\sin (\frac{\pi}{3})=\frac{x\sqrt[]{3}}{2x}\Rightarrow\sin (\frac{\pi}{3})=\frac{\sqrt[]{3}}{2}[/tex][tex]\cos (\frac{\pi}{3})=\frac{x}{2x}\Rightarrow\cos (\frac{\pi}{3})=\frac{1}{2}[/tex][tex]undefined[/tex]

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