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A rock is dropped from a bridge to the water below. It takes 3.2 s for the rock to hit the water. Find the speed (in m/s) of the rock as it hits the water. How high (in m) is the bridge above the water

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osprey2015
Kinematic equations 
v=at. v=9.81x3.2 v=32m/s (approx)
v^2=2axheight.
32x32/2x10=height
16x32/10 = height
height is approx 48metres

Speed of rock and Height of bridge is 31.36 m/s and 50.176 meter

Given that;

Time taken by rock = 3.2 seconds

Find:

  • Speed of rock
  • Height of bridge

Computation:

First equation of motion;

v = u + at

v = 0 + (9.8)(3.2)

Speed of rock = 31.36 m/s

Second equation of motion;

s = ut + [1/2]at²

s = (0)(3.2) + [1/2](9.8)(3.2)²

s = [4.9][10.24]

Height of bridge = 50.176 meter

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