Six red marbles, 4 green marbles and 2 blue marbles are placed in a jar. What is the probability of selecting a green marble and then another green marble given the first marble is not returned to the jar after it is drawn?
There are 6+4+2=12 total marbpee P( green marble):4/12=1/3 P( another green marble without replacing): 3/11 As a result, the probability of selecting a green marble and then another green marble given the first marble is not returned to the jar after it is drawn is 1/3×3/11=3/33 or 1/11. Hope it help!
