Answer:\(\frac{9y^{-2}}{4x^{-2}}\)
Step-by-step explanation:
\(\left(\frac{2x}{3x^{2}y^{-1}}\right)^{-2}\)
\(\left(\frac{2y}{3x}\right)^{-2}\)
\(\frac{(2y)^{-2}}{(3x)^{-2}}\)
\(\frac{2^{-2}y^{-2}}{(3x)^{-2}}\)
\(\frac{\textcolor{#C58AF9}{\frac{1}{4}}y^{-2}}{(3x)^{-2}}\)
\(\frac{\frac{y^{-2}}{4}}{\frac{x^{-2}}{9}}\)
