Seudónimo
Seudónimo
10-08-2014
Mathematics
contestada
C= 1/2h(q+z) for q
solve for q
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Аноним
Аноним
10-08-2014
[tex]C=\frac{1}{2}h(q+z)\\\\\frac{1}{2}h(q+z)=C\ \ \ \ |multiply\ both\ sides\ by\ 2\\\\h(q+z)=2C\\\\hq+hz=2C\ \ \ \ |subtract\ hz\ from\ both\ sides\\\\hq=2C-hz\ \ \ \ |divide\ both\ sides\ by\ h\neq0\\\\q=\frac{2C-hz}{2}[/tex]
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biya
biya
10-08-2014
c=h/2(q+z)
c=(hq+hz)/2
2c=hq+hz
2c-hz=hq
(2c-hz)/2=q
Answer Link
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